If the tip of the syringe, "The Titrator", was not filled with NaOH before the initial volume reading was recorded, would the concentration of acetic acid in vinegar of that trial be greater than or less than the actual concentration? Please explain your answer about why it would be greater or less than.
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If the tip of the syringe, "The Titrator", was not filled with NaOH before the initial...
Section DATA SHEET: EXPERIMENT 16 Date A. Determination of NaOH Concentration 1. Molarity of HCl solution M Trial #1 Volume of acid 0.0831 Trial #2 Trial #3(...) 25.00 ml 25.00_ml 25.00 ml 160.40 ml 5.55_ml 18.75 ml 1.30_mi 0.25_ml. 3.80 ml 3. Final buret reading Initial buret reading 5. Volume of NaOH - 6. Molarity of NaOH (Show set-up) 7. Average molarity of NaOH Analysis of Vinegar (Acetic Acid) Advertised % Acetic Acid Trial #1 Trial #2 Trial #3(...) Volume...
Exp 9 titration of vinegar procedure b
molarity of NaOH = .0859
ROCEDURE B. DETERMINATION OF CONCENTRATION OF ACETIC ACID IN UNKNOWN SAMPLES Titration of vinegar solutions Trial 1 Trial 2 Trial 3 1. Volume of vinegar solution being titrated in milliliters (mL) 25.00 mL 25.00 mL 25.00 ml 2. Volume of vinegar solution being titrated in Liters (L) 0.0250 L 0.0250 L 0.0250 L 3. Final buret reading in ml 16. 20m 16.316L 16.25ml 4. Initial buret reading in...
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Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3 Mass of Vinegar (6) Volume of Vinegar (ml) Density - 1.005 g/ml Initial NaOH volume in syringe (ml) Final NaOH volume in syringe (ml) Volume of NaOH delivered (mL) Volume of NaOH delivered (L) Molarity of NaOH Moles of NaOH delivered Reaction of NaOH with Acetic Acid Moles of Acetic Acid in vinegar sample Molar mass of Acetic...
1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used in each trial = 0.20M 3. Volume of NaOH used in trail#1 (Final – Initial buret reading) = __17.80______ mL 4. Volume of NaOH used in trail#2 (Final – Initial buret reading) = ___18.20_____ mL 5. Average Volume of NaOH used = (#3 + #4) / 2 = ___18______ mL 6. Calculate Molarity of Acetic acid in vinegar = _________ M ?????? (molarity of...
Need help filling out the rest of the table,
please.
1 M of NaOH
5% of acidity of acetic acid (vinegar)
n out Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3 Mass of Vinegar 419 Volume of Vinegar Density 1.005 g/ml Initial NaOH volume in syinge OmL Final NoOH volume in syringe 5.8m Volume of NaOH Delivered i mL 3. b ?? Moles of NaOH Delivered Moles of Acetic Acid...
45 THE TITRATION OF VIR EXPERIMENT 8 REPORT SHEET Name Section Date Attach your completed Post-Lab Questions to this Report Sheet to hand in next week. INTRODUCTION By titrating vinegar with a standardized solution of sodium hydroxide, the experimental % acetic acid in the vinegar was determined and compared to the manufacturer's reported value. DATA 5% acetic acid on vinegar Trial 1 Trial 2 Trial 3 Volume of Vinegar Used (mL) Mass S Vinegar Reported on Bottle Concentration of NaOH...
Lab Report: Titration of Vinegar Experimental Data Trial 1 Trial 2 Initial Buret Reading Trial 3 OML OML OML Final Buret Reading 40 6 ML 40-3 ML 41-7 ML Volume of NaOH used 40.0ML 4 7 40.3 ML Molarity of NaOH used Volume of vinegar used 5ML SML 5ML Data Analysis 1. Write the balanced equation for the neutralization reaction between aqueous sodium hydroxide and acetic acid. The Molarity of Acetic Acid in Vinegar Trial 1 Trial 2 Trial 3...
What information then do you need? This is Chem 2 and not Org
Chem.
Titration of Vinegar Lab Report 1 /25 pts) Name: Part 1: Data and Calculations mass KHC.H.O. - 4.0744 g Molecular Weight potassium hydrogen phthalate KHC.H. - [1 pt) #moles KHP = [0.5 pts) Volume of solution = 250 ml_ L10.5 pts] Concentration of KHP = Mop = _M (1 pt) Volume of KHP Solution to be titrated mL = [1 pt) #mols of KHP to be...
The table filled is the lab run.
Please can you use the three informations provided above to answer
the empty table
Take Density of vinegar = 1.005g/mol
concentration of NaOH = 0.1205M
Experiment #7. Titration of Vinegar Goals 1. To determine the mass percent of acetic acid in a solution via titration. 2. To master the technique of titration. Introduction Vinegar is a common household item that is found in a number of products from salad dressing to cleaners. Vinegar...
I need help calculating the mass percent and with the post lab
question #2.
Part 1 Mass Initial | Final Vol Nall Moles concen. KPHCG (ML) I (m2) Used (m2) KHP (mol)/NaOH(M) 0.28470.00 13.60r 13.600 10.00- 0.1025 2 UZ + ZANT 13.600 24.45 1 10.85 0.001128 10.40 Aug NaOH Concentration (M):0.1032 Part2 Vinegar identification # 4 Vinegar sample date: (011/ Vol Vinegat Initial Final Yol NaOH Mol Acotic Mass Acctic Mass % Titr ULST I OML Used (ml) Acid (mol)...