A hydroelectric power plant has a head of 57 m and spills water at 15 megatonnes of water per day for 20 days. The surface area of the reservoir is 2.0 km^2. What's the power produced by this power plant in MW?
Let us assume all the potential energy is converted into power.
If the plant has head 57 m, then potential energy water flow = ( m g h ) = 15 109 9.8 57 J
flow rate 15 mega tons is per day, hence power produced per day = ( 15 109 9.8 57 ) / (24 3600) = 97 MW
power produced in 20 days = 97 20 = 1940 MW
A hydroelectric power plant has a head of 57 m and spills water at 15 megatonnes...
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