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A hydroelectric power plant has a head of 57 m and spills water at 15 megatonnes...

A hydroelectric power plant has a head of 57 m and spills water at 15 megatonnes of water per day for 20 days. The surface area of the reservoir is 2.0 km^2. What's the power produced by this power plant in MW?

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Answer #1

Let us assume all the potential energy is converted into power.

If the plant has head 57 m, then potential energy water flow = ( m g h ) = 15 109 9.8 57 J

flow rate 15 mega tons is per day, hence power produced per day = ( 15 109 9.8 57 ) / (24 3600) = 97 MW

power produced in 20 days = 97 20 = 1940 MW

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