Can someone please help me with this problem? I am having trouble with figuring it out. Thank you in advanced! The 10x objective has a numerical aperture of 0.25. What would be the smallest distance (in μm) between two objects that can be resolved when using that objective with light at 400 nm?
The smallest distance between two objects that can be resolved by a microscope is known as resolution of that microscope and the resolution of a microscope is given by the formula: Resolution (r) = λ/(2NA) where λ = wavelength of light and NA = numerical aperture. Here the λ is given as 400 nm (0.4 μm) and NA is given as 0.25. Thus,
r = 0.4/ 0.25 = 1.6 μm
Thus, the smallest distance (in μm) between two objects that can be resolved is 1.6 in μm.
Note: Here answer is required in μm therefore wavelength of light (400 nm) has been converted into μm.
Can someone please help me with this problem? I am having trouble with figuring it out....
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