Consider a probability tree for selecting two puppies without replacement. The joint probability of two branches...
Consider a probability tree for selecting two puppies without replacement. The joint probability of two branches of the probability tree where the first selection is P(F)= 2/7 and the second selection P(F/F))= 3/10 is ______.
a. P(FF)=(5/17)
b. P(FF)= (2/7) (3/10)
c. P(FF)= (2/7/3/10)
d. P(FF)=22
Homework Answers
Using conditional probability formula,
P(F | F) = P(FF ) / P(F)
So,
P(FF) = P(F | F) * P(F)
= (2/7) * (3/10)
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