A capacitor has a capacitance of 5.48 pF. What is the charge on the positive plate when the magnitude of the potential difference between the plates is 13.2 V?
To find the charge on the positive plate of the capacitor, we can use the formula for the capacitance of a capacitor:
Q = C * V
Where: Q = Charge on the capacitor (in coulombs) C = Capacitance of the capacitor (in farads) V = Potential difference between the plates (in volts)
Given: Capacitance (C) = 5.48 pF = 5.48 x 10^-12 F (convert from pF to farads) Potential difference (V) = 13.2 V
Now, plug the values into the formula:
Q = 5.48 x 10^-12 F * 13.2 V
Q ≈ 7.2336 x 10^-11 coulombs
The charge on the positive plate of the capacitor is approximately 7.2336 x 10^-11 coulombs.
A capacitor has a capacitance of 5.48 pF. What is the charge on the positive plate...
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