Molarity of 20ml pure water Kf=1.86 C/molal
The freezing point of water, H2O, is 0.000 °C at 1 atmosphere. Kf(water) = 1.86 °C/m In a laboratory experiment, students synthesized a new compound and found that when 11.53 grams of the compound were dissolved in 218.3 grams of water, the solution began to freeze at -0.287 °C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound? ??? g/mol
The freezing point of water, H2O, is 0.000 °C at 1 atmosphere. Kf(water) = -1.86 °C/m In a laboratory experiment, students synthesized a new compound and found that when 12.85 grams of the compound were dissolved in 200.2 grams of water, the solution began to freeze at -1.986 °C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound ? _______________ g/mol
A solution of water (Kf=1.86 ∘C/m) and glucose freezes at − 2.35 ∘C. What is the molal concentration of glucose in this solution? Assume that the freezing point of pure water is 0.00 ∘C. Express your answer to three significant figures and include the appropriate units. View Available Hint(s) m m m = nothing nothing Submit Boiling points and molality Similar to the freezing-point depression, the boiling-point elevation ΔTb of a solution is quantitatively related to the molality m and...
The freezing point of water, H2O, is 0.000 °C at 1 atmosphere. Kf(water) = -1.86 °C/m In a laboratory experiment, students synthesized a new compound and found that when 10.77 grams of the compound were dissolved in 268.4 grams of water, the solution began to freeze at -1.202 °C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound ?
The freezing point of water, H2O, is 0.000 °C at 1 atmosphere. Kf(water) = 1.86 °C/m In a laboratory experiment, students synthesized a new compound and found that when 14.38 grams of the compound were dissolved in 227.9 grams of water, the solution began to freeze at -0.343 °C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound?
1h. A certain pure solvent freezes at 39.8°C and has a freezing point depression constant Kf = 0.777°C/m. What is the predicted freezing point (in °C) of a solution made from this solvent that is (1.90x10^0) m in a non-electrolyte solute? 1i. When (8.23x10^1) g of a non-electrolyte is dissolved in (5.2600x10^2) g of a solvent (with Kb = 0.416°C/m) the boiling point of the solution is 1.50°C higher than the boiling point of the pure solvent. What is the...
What is the freezing point in ∘C of each of the solutions below? For water, Kf = 1.86(∘C ⋅ kg)/mol. A solution of 15.0 g of LiCl in 168.0 g of water at 45.0 ∘C, assuming complete dissociation.
For water, Kf = 1.86 °C∙kg/mole, Kb = 0.52 °C∙kg/mole and density = 1.00 g/mL. Calculate the boiling and freezing points of the following aqueous solutions: a) 18.4 g of glucose (C6H12O6) in 95.5 g of water. b) 15.0 g of magnesium fluoride in 75.0 mL water.
What mass of lithium phosphate must be added to 25.0 L of water (Kf = 1.86 °C/m) to produce a solution that freezes at -5.2 °C and what is the molarity of the lithium ions in this solution when the density=2.34g/mL