Question

consider the aqueous reaction of Cl2 + H2S -> S + 2HCL . It may happen...

consider the aqueous reaction of Cl2 + H2S -> S + 2HCL . It may happen by the following mechanism

1: Cl2-> <- 2Cl fast

2: Cl+H2S -> <- HCl + HS fast

3: HS +Cl --> --< HCl + S slow

DERIVE a rate law for overall reaction using the given mechanism and rate determining step without using intermediates in the rate law.

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Answer #1

Solution:

For the given reaction,

There are two transient species (HS and Cl). Therefore rate expession is calculated by using steady state approximation (ssa).

Suppose rate constants for the given three steps are k1,k2 and k3 respectively.

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