Adding to Newton’s law of universal gravitation, the gravitational force between two masses is proportional to 1/r^2, where r is the distance between the masses. Surprisingly, the electric force between two electric charges is also proportional to 1/r^2, where r is the distance between the electric charges. (Coulomb’s law) These facts are called the “inverse-square laws” -> Now give “your answer” to the question: Why (or How) are these forces proportional to 1/r^2 (not 1/r, 1/r^3, 1/r^100, etc)?
The electrostatic force is the force between the two charges and gravitational force is between two masses.
The logic of the inverse square law comes from the experimental data.
When the Newton study about these forces then he collect the experimental data and arrange according to the order. Then he see that the force depends upon the distance between the two particles. For the exact dependency of the distance he makes curves for these forces ans see that the variation is depends upon inverse of square.
And the formula is valid at each and every case at all conditions. So, he conclude and come to the result that the Gravitational and Electrostatic force depends upon inverse of square.
The experimental data need no Proof.
Thanks.
Adding to Newton’s law of universal gravitation, the gravitational force between two masses is proportional to...
Given Newton's law of universal gravitation where F is the force between two masses objects, m1 and m2 are the masses of the two bodies and r is the distance between the two bodies. Determine the units of G in two ways 1) including Newtons, N, as one of the units and 2) not including N. (hint...if you don't recall what the dimensions of N are, think of Newton's second law!
Two 639-kg masses are separated by a distance of 0.15 m. Using Newton's Law of Universal Gravitation, find the gravitational force of attraction between these two masses.
Newton's law of universal gravitation provides a theory that describes the force of attraction of between two masses separated by a certain distance. Scientific ideas must be testable and withstand repeated tests to be considered a theory. Describe two predictions of the universal law of gravitation that have been verified by measurement.
Laboratory Unversal Gravitational Law please answer all 3 cases. thank you Laboratory universal gravitational law Answer all cases please. (Equation 11 Where: - mass of one object in ks - mass of the other object in kg G-Newton's Universal Gravitational Constant r - distance between the two masses in meters Case 1: Glven two masses. - 100 kg = 400 kg, and the attractive force between the two masses is Newtons Case 2: Glven two masses... 230 kg. - 280...
Learning Goal: To understand Newton's law of gravitation and the distinction between inertial and gravitational masses. In this problem, you will practice using Newton's law of gravitation. According to that law, the magnitude of the gravitational force Fg between two small particles of masses m1 and m2 separated by a distance r, is given by m1m2 T2 where G is the universal gravitational constant, whose numerical value (in SI units) is 6.67 x 10-11 Nm2 kg2 This formula applies not...
Using Newton’s law of gravitation, find the centripetal acceleration of a satellite orbiting the Earth at a distance of R = 12×106 m. What is the angular velocity of that satellite? What is the period of motion? Earth’s mass: ME = 5.973×1024 kg Universal Gravitational constant: G = 6.674×10−11 m3kg−1s−2.
Two 700-kg masses (1543 lb) are separated by a distance of 45 m. Using Newton’s law of gravitation, find the magnitude of the gravitational force exerted by one mass on the other. (Use G = 6.67 × 10-11 N·m2/kg2.) (Round the final answer to four decimal places.) The magnitude of the gravitational force exerted by one mass on the other is _____× 10–9 N.
a. Two 700-kg masses (1543 lb) are separated by a distance of 33 m. Using Newton’s law of gravitation, find the magnitude of the gravitational force exerted by one mass on the other. (Use G = 6.67 × 10-11 N·m2/kg2.) (Round the final answer to four decimal places.) The magnitude of the gravitational force exerted by one mass on the other is ___________ × 10–9 N. b. Two masses are attracted by a gravitational force of 0.36 N. What will...
Use Newton's law of universal Gravitation to estimate force exerted by one object on another: F = G m_1 m_2/r^2 In which m_1 and m_2 are masses of object 1 and 2 in kg, and r is the distance between the two in meters. G is universal gravitational constant equal to 6.673 * 10^-11 Nm ^2/kg^2. What is the force that moon (m_l = 7.4 * 10^22 kg) exerts to earth (m_2 = 6 * 10^24 kg) knowing that they...
Can you please give me the whole solution for this question! Thanks 2. According to Newton's Law of Universal Gravitation, the gravitational force on an object of mass m that has been projected vertically upward from Earth's surface is F( is the objer s distan boe he urfac at time t, Ris Earth's radius, ngR (x+R)2 and g is the acceleration due to gravity. Also, by Newton's Second law, mgR2 (x +R)2 dv F = mal = m dt =...