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8. A solution was prepared by mixing 50 μL of 8 mg/mL octadecane internal standard with...

8. A solution was prepared by mixing 50 μL of 8 mg/mL octadecane internal standard with 100 μL of 12 mg/mL of a dodecane standard with 350 μLhexane. The octadecane peak area was 357 while the dodecane area was 516. Calculate the Response Factor.

9. The same internal standard was used to prepare an unknown sample of dodecane. The sample

was prepared by mixing 50 μL of 8 mg/mL octadecane and 100 μL dodecaneof unknown

concentration. The areas were 382 for octadecane and 463 for dodecane. Calculate the unknownconcentration. Remember to use significant figures.

Please solve question 9.

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