At a certain temperature, Keq = 150 for the reaction being studied in today’s lab. Use Equation (3) to calculate the concentrations of Fe3+ and SCN in a solution that has an equilibrium FeSCN2+ concentration of 4.5 x 10-5 M. Assume the equilibrium concentrations of Fe3+ and SCN are equal.
At a certain temperature, Keq = 150 for the reaction being studied in today’s lab. Use...
Equilibrium Concentrations for a Simple Addition Reaction At a certain temperature K = 1.10x103 for the reaction: Fe3+(aq)SCN"(aq) FeSCN2+(aq) 5.00x102 mol of Fe(NO3)3 is added to 8.70x 10-1 L of 1.84 x 10-1 M KSCN. Neglecting any volume change and assuming that all species remain in solution--: Calculate the equilibrium concentration of Fe3+ (in mol/L) mol/L 1 pts 提交答案 Tries 0/8 Calculate the equilibrium concentration of SCN (in mol/L). mol/L 1 pts [提交答案 Tries 0/8 Calculate the equilibrium concentration of...
At a certain temperature, K = 8.60 x 10^-4. for the reaction FeSCN2+(aq) ⇄ Fe3+(aq) + SCN-(aq) Calculate the concentrations of Fe3+, SCN-, and FeSCN2+ in a solution that is initially 2.0 M FeSCN2+.
Equilibria can be treated mathematically with the equilibrium constant, K. For the reaction Fe3+ + SCN − equilibrium reaction arrow FeSCN2+, the equilibrium constant expression is [FeSCN2+ ] K = [Fe3+ ] · [SCN − ] where, for example, [Fe3+ ] is the molar concentration (mol Fe3+ / L solution) present in an equilibrium mixture. At some temperature, a chemist found the following equilibrium concentrations. [Fe3+ ] = 8.17 ✕ 10−3 M, [SCN − ] = 8.60 ✕ 10−3 M,...
For each equilibrium sample, calculate the initial concentrations (assuming no reaction occurred) of SCN– and Fe3+ based on the dilution factors used. Enter the absorbance values for each sample. For the standard solution, assume that, when equilibrium is reached, the [FeSCN2+]eq is equal to [SCN–]ini. Why is this a good assumption? For the equilibrium solutions, calculate the [FeSCN2+]eq (Ceq) using Eq. 4. Using Eq. 5 and 6, calculate [Fe3+(aq)]eq and [SCN–(aq)]eq for each equilibrium solution. Calculate values for the equilibrium...
Use the mean value of 540 for Keq to calculate the SCN- concentration in a solution whose initial Fe3+ concentration was 3.60x10-2 M and initial SCN- concentration was 1.30x10-3 M. Give answer in M. Equation: Fe3+ + SCN- <-----------> FeNCS2+
Consider the following: A student mixes 5.00 mL 2.00 × 10−3 M Fe(NO3)3 with 3.00 mL 2.00 × 10−3 M KSCN. She finds that in the equilibrium mixture the concentration of FeSCN2+ is 1.28 × 10−4 M. Find Kc for the reaction Fe3+(aq) + SCN−(aq) ↔ FeSCN2+(aq). a. What is the initial concentration of Fe3+ in the reaction mixture? [Fe3+] = ___ x 10-3 M b. What is the initial concentration of SCN- in the reaction mixture? [SCN-] = ___...
Use the mean value of 533 for Keq to calculate the SCN− concentration in a solution whose initial Fe3+ concentration was 4.10×10−02 M and initial SCN− concentration was 1.50×10−03 M Fe3+ +SCN- --->FeNCS2+
thiocyanatoiron (III)ion? The path length for the light is 1.00 cm? FE(NO3)₂ + KSCN sre(SCN) KT + 3No. [NOPZ Keq & [Lee SCN ) 2+] [x+) Tre(NO3); [ilsen . 1.4 x 10² x (1-x)² = 23 x 3 X 0.77 m Keqz (3x) I Toro-x) (2.00 X 2. Assuming that the equilibrium concentration of [FeSCN2') is 6.08 x 10 Min a solution that initially was 1.00 x 10 Min Fe3+ and 2.00 x 10 Min SCN, calculate the equilibrium concentrations...
Consider the reaction represented by the equation: Fe3+ (aq) + SCN- (aq) FeSCN2+ (aq) What is the equilibrium concentration of FeSCN2+ (aq) if a solution is prepared that is initially 6.00 M Fe3+ (aq) and 6.00 M SCN− (aq)? if k was determined to be 0.333
4.81 mL of 0.00200 M Fe(NO3)3, 2.85 mL of 0.00200 M KSCN and 2.34 mL of distilled water were mixed. The resulting solution was allowed to attain equilibrium at 24 oC. The absorbance of the equilibrium solution was recorded, and the [FeSCN2+] was determined graphically to be 7.58 x 10-5 M. Part A: Calculate the number of moles of Fe3+ initially added to the solution. Part B: Calculate the number of moles of FeSCN2+ formed in the solution at equilibrium....