The air pollutant NO is produced in automobile engines from the
high-temperature reaction:
N2(g)+O2(g)⇌2NO(g)Kc=1.7×10−3.
Calculate the equilibrium concentrations if the initial concentrations are 2.28 M N2 and 0.56 M O2. (This N2/O2concentration ratio is the ratio found in air.)
Express your answer using two significant figures. Enter your answers numerically separated by commas.
The air pollutant NO is produced in automobile engines from the high-temperature reaction: N2(g)+O2(g)⇌2NO(g)Kc=1.7×10−3. Calculate the...
The air pollutant NO is produced in automobile engines from the high-temperature reaction N2(g)+O2(g)⇌2NO(g);Kc=1.7×10−3 at 2300 K. If the initial concentrations of N2 and O2 at 2300 K are both 1.58 M, what are the concentrations of NO when the reaction mixture reaches equilibrium? Concentrations of NO= UNITS If the initial concentrations of N2 and O2 at 2300 K are both 1.58 M, what are the concentrations of N2 when the reaction mixture reaches equilibrium? Concentrations of O2= If the...
The reaction N2(g)+O2(g)⇌2NO(g) is carried out at a temperature at which Kc = 0.050. The reaction mixture starts with only the product, [NO] = 0.0300 M , and no reactants. Part A Find the equilibrium concentrations of N2 at equilibrium. Express your answer to two significant figures and include the appropriate units. [N2] = Part B Find the equilibrium concentrations of O2 at equilibrium. Part C Find the equilibrium concentrations of NO at equilibrium. Express your answer to two significant figures...
Problem 7: Nitric oxide, NO, is a common air pollutant produced by automobile engines and power plants according to the reaction N2 (g)+02 (g) 2NO (g) A constant-volume reactor of 100 L is initially charged with 4 mol of N2 and 1 mol of O2 and then temperature is increased to 800 K. Estimate the equilibrium extent of the reaction if the pressure is kept constant at 1 bar (Answer: 5.567 x 10-6)
The reaction below is carried out at a different temperature at which Kc=0.055. This time, however, the reaction mixture starts with only the product, [NO]=0.0100M [NO]=0.0100M, and no reactants. Find the equilibrium concentrations of N2, O2, and NO at equilibrium. N2(g)+O2(g)⇌2NO(g) Express your answers to three significant figures separated by commas.
find equilibruim concentrations of O2, N2 and NO The reaction N2(g) + O2(g) = 2NO(g) is carried out at a temperature at which Kc = 0.045. The reaction mixture starts with only the product, (NO) = 0.0300 M, and no reactants.
For the reaction N2(g) + O2(g) 2NO(g), Kc = 4.0 at a particular temperature. In a 1.0-L container, 1.0 mol of N2 and O2 are mixed. Determine the concentration of NO once equilibrium is reached at the given temperature. =________ Please explain so I understand
Automobiles and trucks pollute the air with NO. At 2000.0°C, Kc for the reaction $$N2(g)+O2(g)2NO(g) At 2000.0°C Kc = 4.100 × 10–4 and ΔH° = 180.6 kJ. 1st attempt What is the value of Kc at 43.00°C?
The reaction N2(g) + O2(g) ⇄ 2 NO(g) contributes to air pollution whenever a fuel is burned in air at a high temperature, as in a gasoline engine. At 1500 K, Kc = 1.0×10-3. Suppose a sample of air has [N2] = 0.70 mol/L and [O2] = 0.20 mol/L before any reaction occurs. Calculate the equilibrium concentrations of reactants and products after the mixture has been heated to 1500 K. [N2] = M [O2] = M [NO] = M
Consider the following reaction: A(g)⇌B(g)+C(g) Find the equilibrium concentrations of A, B, and C for each of the following different values of Kc. Assume that the initial concentration of A in each case is 1.0 M and that the reaction mixture initially contains no products. Make any appropriate simplifying assumptions. Part A Kc= 1.8 Express your answer using two significant figures. Enter your answers numerically separated by commas. [A][ A ], [B], [C] = nothing M
QUESTION 12 BEE [CLO-6] At 2000 °C, the equilibrium constant for the reaction: 2NO(g) N2(g) + O2(g) Is Kc = 2.4. Knowing that the initial concentration of NO is 0.175 M, what will be the concentrations of NO, N2 and O2 at equilibrium? [Hint: you have to build a table to find the answer) (0.175), +2x, +2x (0.175), +x, +x +x (0.175-2x), +x, (0.175-x), +x, +X