Use Hess’s Law to find the standard enthalpy change for the reaction CO2(g) → C(s) + O2(g)
using only the following information. Show all your work, including any equations you use to obtain your answer and showing clearly how you obtained that answer. (3 pts.)
H2O(l) → H2(g) + 1/2O2(g)
C2H6(g) → 2C(s)+ 3H2(g)
2CO2(g) + 3H2O(l) → C 2H6(g) + 7/2O2(g)
∆Ho (kJ) 643 kJ 190.6kJ
3511.1 kJ
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Use Hess’s Law to find the standard enthalpy change for the reaction CO2(g) → C(s) +...
problem is together. 3. Calculate the enthalpy of formation of carbon dioxide in the following reaction: C(s) + O2(g) - CO, (g) Use the following equations: a) H2O(l) → H2(g) + 2O2(g) AH°-= +285.8 kJ/mol b) C2H6(g) → 2C (s) + 3H2(g) AH'= +84.7 kJ/mol c) 2CO2 (g) +3H2O (1) C2H6(g) + (7/2) O2(g) AH°F = +1560.7 kJ/mol
Part 1) Use the following equations to calculate the heat of the reaction for the formation of ethane (C2H6). C2H6(g) + 7/2 O2(g) → 2CO2(g) + 3 H2O(l) ∆ Ho = -1560 kJ C(gr) + O2(g) → CO2(g) ∆ Ho = -394 kJ H2(g) + 1/2 O2(g) → H2O(l) ∆ Ho = -286 kJ Calculate ∆Ho for the following reaction: 2 C(gr) + 3H2(g) → C2H6(g) ethane Use kJ for your answer. ΔHo = Part 2) Find the heat of...
Calculate the change in enthalpy (ΔH) for the heat of formation of ethane, C2H6, using Hess' Law and the following reactions:a) 2C(S) + 2O2(g) → 2CO2(g), ΔH = -188 kcalb) C2H6(g) + (7/2)O2(g) → 2CO2(g) + 3H2O(l), ΔH = -373 kcalc) H2(g) + (1/2)O2(g) → H2O(l), ΔH = -68.3 kcal
Use Hess’s law to calculate ∆H° for the reaction:C(s) + 2H2(g) + ½O2(g) → CH3OH(l) ∆H°∘= ?using only the following data:H2(g) + ½O2(g) → H2O(l) ∆H°= -285.8 kJC(s) + O2(g) → CO2(g) ∆H°= -393.5 kJ2CH3OH(g) + 3O2(g) → 2CO2(g) + 4H2O(l) ∆H°= -1452.8 kJ
Find the change in enthalpy for the reaction below, given the following reactions and change in enthalpy values: C2H2(g)+ 5/202(g)-2CO2(g) + H2O(g) ΔΗ ? Use: C2H6(g) → C2H2(g) + 2H2(g) ΔΗ : 283.5 kJ H29) 1/2029) H20(g) AH--213.7 kJ 2CO2(g) + 3H2O(g)-C2H6(g) + 7/2O2(g) ΔΗ = 849 kJ
Use the following information and hess's law to find the enthalpy change for the reaction C(g) + O2(g) => CO2(g) reaction 1: 2CO(g) + O2(g) => 2CO2(g) ΔH = -566 kj reaction 2: 2C(g) + O2(g) => 2CO(g) ΔH = -1655 kj
3. Calculate the enthalpy of formation of carbon dioxide in the following reaction: C(s) + O2 (g) – CO2 (g) 213 Use the following equations: a) H20 (0) -- H2(g) + 103() AH',- +285.8 kJ/mol b) CH. (g) -2C (s) + 3H2(g) AH:- +84.7 kJ/mol c) 2CO2(g) +3H() - CH.(g) + (7/2) O, (g) AH,- +1560.7 kJ/mol
Use the enthalpies for the given reactions to compute the standard enthalpy change (ΔH°) for the reaction: 6 C (s) + 7 H2(g) → C6H14 (l) ΔHrxn = ? C6H14 (l)+19/2O2 (g)→6CO2(g)+ 7H2O(g). ΔH=–3505.8kJ C(s) + O2 (g) → CO2(g) ΔH=–393.5kJ H2(g) + 1/2 O2(g) → H2O(g). ΔH = – 242.0 kJ
Calculate the enthalpy of the following reaction: C (s) + 2 H2 (g) --> CH4 (g) Given: C (s) + O2 (g) --> CO2 ΔH = -393 kJ H2 + 1⁄2O2 --> H2O. ΔH = -286 kJ CH4 + 2O2 --> CO2 + 2H2O ΔH = -892 kJ
a) Use Hess's law to calculate the enthalpy change for the reaction: 3C(s) + 4H2(g) + ½O2(g) → C3H8O(l) Given the following thermochemical equations: 2C3H8O(l) + 9O2(g) → 6CO2(g) + 8H2O(l) ΔH = -4042.6 kJ/mol C(s) + O2(g) → CO2(g) ΔH = -393.51 kJ/mol H2(g) + ½O2(g) → H2O(l) ΔH = -285.83 kJ/mol (in kJ/mol) A: -267.7 B: -302.6 C: -341.9 D: -386.3 E: -436.5 F: -493.3 G: -557.4 H: -629.9 b) Define if the following statement is an endothermic process or exothermic...