Question

A meat packaging plant uses a machine that packages ground chuck in eight ounce portions. A...

A meat packaging plant uses a machine that packages ground chuck in eight ounce portions. A sample of 15 packages of ground chuck has a variance of 0.41. Construct the 80% confidence interval to estimate the variance of the weights of the packages prepared by the machine.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution:-

80% confidence interval to estimate the variance of the weights of the packages prepared by the machine is .

n = 15, variance = 0.41

Add a comment
Know the answer?
Add Answer to:
A meat packaging plant uses a machine that packages ground chuck in eight ounce portions. A...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A meat packaging plant uses a machine that packages ground chuck in two pound portions. A...

    A meat packaging plant uses a machine that packages ground chuck in two pound portions. A sample of 11 packages of ground chuck has a standard deviation of 0.14. Construct the 98% confidence interval to estimate the standard deviation of the weights of the packages prepared by the machine. Round your answers to two decimal places.

  • A commercial farm uses a machine that packages strawberries in six ounce portions. A sample of...

    A commercial farm uses a machine that packages strawberries in six ounce portions. A sample of 19 19 packages of strawberries has a variance of 0.41 0.41 . Construct the 80% 80 % confidence interval to estimate the variance of the weights of the packages prepared by the machine. Round your answers to two decimal places.

  • Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack...

    Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of a shift 15 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 15 bags yielded the following data. mean = 19.45 s = .64 n = 15. A 90% confidence interval would have what as the lower and upper bounds?

  • Question 14 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its...

    Question 14 3 pts Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s=.80 n = 18. A 95% confidence interval would have what as the Bound of Error? 20.052...

  • Orange 52. Juice Dispensing Machine A beverage company uses a machine to fill half-gallon bottles with...

    Orange 52. Juice Dispensing Machine A beverage company uses a machine to fill half-gallon bottles with fruit juice (see figure). The company wants to estimate the mean volume of water the machine is putting in the bottles within 0.25 fluid Ounce. (a) Determine the minimum sample size required to construct a 95% confidence interval for the population mean. Assume the population standard deviation is 1 fluid Ounce. (b) The sample mean is exactly 64 fluid ounces. With a sample size...

  • Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack...

    Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s= .80 n = 18. If we were to conduct a test to see if the sample estimate is different from...

  • Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack...

    Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s = .80 n = 18. If we were to conduct a test to see if the sample estimate is different...

  • A paint manufacturer uses a machine toll gallon cars with paint (1 128 ounces). The manufacturer...

    A paint manufacturer uses a machine toll gallon cars with paint (1 128 ounces). The manufacturer wants to estimate the mean volume of paint the machine is puting in the card within 0.5 ounce Assume the population of volumes is normally distribuid. (8) Determine the minimum sample size required to constructa 90% confidence interval for the population mean. Assume the population standard deviation is 0.71 ounce (0) The sample meanis 126.75 ounces with a sample size of 9, a 90%...

  • Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack...

    Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. 18 mean 20.45 s = .80 n = If we were to conduct a test to see if the sample estimate is different from...

  • Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack...

    Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At the end of every shift 18 bags are selected at random and tested to see if the equipment needs to be readjusted. After one shift, a sample of 18 bags yielded the following data. mean = 20.45 s = .80 n = 18. If we were to conduct a test to see if the sample estimate is different...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT