A number of mutants were isolated in yeast that are auxotrophic for leucine. Different crosses were...
A number of mutants were isolated in yeast that are auxotrophic for leucine. Different crosses were performed between the different Leu- strains. In which of the following crosses would a geneticist expect the resulting diploid to grow on medium lacking leucine?
A. A diploid containing two mutant alleles of the same gene that have the same nucleotide sequence.
B. A diploid containing two mutant alleles of the same gene that have different nucleotide sequences.
C. A diploid with a point mutation in one gene and a deletion in
a different gene.
D. A diploid with a point mutation in one gene and a deletion
mutation in the same gene.
Homework Answers
C). A diploid with a point mutation in one gene and a deletion in a different gene.
Different mutants will have different mutations at different gene that participates in different genes involved in leucine utilisation oathway and upon crossing if both have mutation at different gene, due to complementary effect it will result in diploid that can grow in leucine
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A number of mutants were isolated in yeast that are auxotrophic
for leucine. Different crosses were...
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please help with part A and B.
2. A yeast geneticist isolates two different haploid mutant yeast strains, Strain A and Strain B, which cannot grow unless the amino acid leucine is added to the growth media. Wild-type yeast strains can make their own leucine and do not require that it be added to the growth media. The geneticist discovers that each mutant yeast strain contains a single recessive mutation that leads to the observed leucine-requiring phenotype. When she crosses...
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What mutants are in the same complementation group as M2? Select as many as apply. Question...
What mutants are in the same complementation group as
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18. Shown below are the results of a series of coinfections of E. coli B using T4 rll- strains similar to those employed by Benzer in his deletion mapping experiment. Each strain contains a different deletion mutation. The ability to produce wild-type progeny phage is indicated by (+), (O) indicates no wild-type progeny. + + OC Which order of deletions is most consistent with this data?...
please help with part A and B.
2. A yeast geneticist isolates two different haploid mutant yeast strains, Strain A and Strain B, which cannot grow unless the amino acid leucine is added to the growth media. Wild-type yeast strains can make their own leucine and do not require that it be added to the growth media. The geneticist discovers that each mutant yeast strain contains a single recessive mutation that leads to the observed leucine-requiring phenotype. When she crosses...
What mutants are in the same complementation group as
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Question 17. Saccharomyces cerevisiae (also called budding yeast or baker's yeast) normally makes LARGE colonies on the Petri dish. The fungus can exist as either a haploid or as a diploid. As a geneticist, you decide to isolate haploid mutants with altered size of colonies. You collect 6 such haploid mutants, which you arbitrarily name M1, M2, M3, M4, M5, and M6. To determine how...
What mutants are in the same complementation group as
M2? Select as many as apply.
Question 17. Saccharomyces cerevisiae (also called budding yeast or baker's yeast) normally makes LARGE colonies on the Petri dish. The fungus can exist as either a haploid or as a diploid. As a geneticist, you decide to isolate haploid mutants with altered size of colonies. You collect 6 such haploid mutants, which you arbitrarily name M1, M2, M3, M4, M5, and M6. To determine how...
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Answers are C,A. Please explain
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