Question

Write a program that first asks the user how many budget items they have. Then using dynamic arrays, create the appropriate arrays to hold the following data:

Allow the user to enter the budget items and amount budgeted for the number items created in the dynamic array. (For your testing, just use four or five.) Once all budget items are entered, the program should then output each budget item, the amount of money budgeted for that item, and the percentage of the total budget for each item. Your program should also calculate and print the total budget amount and print out the highest budget line item. A sample output is:

Budget Item	Amount	% of Total
Mortgage	1300	76.70
Electric	150	8.85
Internet	75	4.42
Cell Phone	120	7.08
Food	50	2.95
Total	1595
Highest Item	Mortgage

By using a struct to hold the data instead of two arrays

I need help with problem its C++. Thank you.

Answer 1

CODE:

#include <iostream>
#include <iomanip>

using namespace std;

//structure to store the item details
struct Items{
  
//stores item name
string item;
  
//stores item amount
double amount;
};

int main()
{
//to store the number of items
int n;
cout<<"Enter the number of budget items: ";
  
//input of number of Items
cin>>n;
  
//initializing n number of items
Items it[n];
  
cout<<"Enter Items name and amount: \n";
  
int sum=0,max=0;
  
//input of details of n items
for(int i=0;i<n;i++){
cin>>it[i].item;
cin>>it[i].amount;
  
//calculating sum of n items amount
sum+=it[i].amount;
  
//if max is smaller than ith items amount, update max
if(max<it[i].amount)
max = it[i].amount;
}
  
cout<<"\nITEM AMOUNT PERCENTAGE\n";
  
//it will print double upto 2 decimal precision
cout<<fixed<<setprecision(2);
  
//printing details of n items and their calculated PERCENTAGE
for(int i=0;i<n;i++){
cout<<it[i].item<<" "<<it[i].amount<<" "<<it[i].amount*100/sum<<"%"<<endl;
}
  
cout<<"Highest amount: "<<max<<endl;
cout<<"Total Amount: "<<sum;
  
return 0;
}

OUTPUT: