Class records at Rockwood College indicate that a student selected at random has probability 0.61 of...
Class records at Rockwood College indicate that a student selected at random has probability 0.61 of passing French 101. For the student who passes French 101, the probability is 0.86 that he or she will pass French 102. What is the probability that a student selected at random will pass both French 101 and French 102? (Round your answer to three decimal places.)
Homework Answers
P(Pass French 101) = 0.61
P(French 102 | French 101) = 0.86
So,
P(French 102 and French 101) = P(French 102 | French 101) * P(Pass French 101)
= 0.86 * 0.61
= 0.525
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