Question 1.
The heat (qtotal) that would be taken by 30 g of copper to melt from 20 oC, can be calculated as shown below.
qtotal = (q)Cu(s) + (q)fusion
= {m.C.(T2-T1)}Cu(s) + m.(Hfus)
Where 'm' is the mass of copper.
'Ç' is the specific heat of copper = 0.093 cal/g.oC
Hfus is the heat of fusion (heat required to melt copper, i.e. from solid to liquid phase) = 32 cal/g
Therefore, qtotal = 30 g*0.093 cal/g.oC*(1083 - 20) oC + 30 g*32 cal/g
= 2965.77 cal + 960 cal
Therefore, the amount of heat that would be taken by 30 g of copper to melt from 20 oC (qtotal) = 3925.77 cal or 3.926 kcal
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