There are 3 empty buckets lined up. Someone takes 4 apples and places each one in...
There are 3 empty buckets lined up. Someone takes 4 apples and places each one in a bucket. The placement of each apple is random and independent of the others. What is the probability that the first two buckets end up with no apples?
(Round your answer to three decimal places. Example: if the true answer is 2/3, you should enter 0.667.)
Homework Answers
The total number of ways of placing four apples into 3 buckets is 43=64 as each apple has 3 options to be placed.
Now number of ways in which the first two buckets end up with no apples is exactly 1 as 3rd bucket is fixed to have all apples. Hence the probability of this even is 1/64 = 0.016
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There are 3 empty buckets lined up. Someone takes 4 apples and
places each one in...
There are 3 empty buckets lined up. Someone takes 4 apples and places each one in...
There are 3 empty buckets lined up. Someone takes 4 apples and places each one in a bucket. The placement of each apple is random and independent of the others. What is the probability that the first two buckets end up with no apples?
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