In a recent year, Delaware had the highest per capita annual income with $51,803. If standard...
In a recent year, Delaware had the highest per capita annual income with $51,803. If standard deviation= $4850, what is the probability that a random sample of 36 state residents had a mean income greater than $50,100
Homework Answers
Solution :
Given that ,
=
/ 
n = 4850 /
36 = 808.3333
P(
> 50100) = 1 - P(
< 50100)
= 1 - P[(
- 
) /
< (50100 - 51803) / 808.3333]
= 1 - P(z < -2.11)
= 1 - 0.0174
= 0.9826
Probability = 0.9826
Solution :
Given that ,
=
/ 
n = 4850 /
36 = 808.3333
P(
> 50100) = 1 - P(
< 50100)
= 1 - P[(
- 
) /
< (50100 - 51803) / 808.3333]
= 1 - P(z < -2.11)
= 1 - 0.0174
= 0.9826
Probability = 0.9826
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