a person runs with an initial velocity of 5.0m/s. then he slows down at a rate of -1.2 m/a square over a period of 3 seconds
initial speed of man(u)=5m/s
acceleration(a)=-1.2m/s^2
time(t)=3sec
distance travelled in this time= (u*t)-(1/2)*a*t^2
=(5*3)-(1/2)*(1.2)*3^2
=15-(0.5*1.2*9)
=9.6m
a person runs with an initial velocity of 5.0m/s. then he slows down at a rate...
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