A 33.0 g silver spoon at 18.2°C is placed in a cup of coffee at 94.1°C. A short time later, the spoon is at 91.1°C.
If, during this same time, the temperature of the coffee has fallen by 0.6°C,what is the mass of the coffee? (csilver = 0.056 cal/g°C and assume ccoffee = 1.0 cal/g°C)
Heat gained by silver spoon = heat lost by coffee
33 × 0.056 × (91.1 - 18.2)= m × 1 × 0.6
m = 224.5 g
A 33.0 g silver spoon at 18.2°C is placed in a cup of coffee at 94.1°C....
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