if the silver spoon placed in the coffee in exercise 6 (THE QUESTION BEFORE THIS) causes it to cool 0.75 C, what us the mass of the coffee?
Assume C coffee = 1.0 cal/gC
please show work
From your previous question, using joules instead of calories (4.2 J = 1 cal), the energy the spoon absorbs from the coffee is 828 J. The answer should still be the same if you use calories.
This must mean that the energy drop of the coffee is also 828 J.
i.e. Qspoon=-Qcoffee
-828 J=mcoffee(4.2 J/goC)(-0.75 oC)
This gives mcoffee=266 grams.
If you wish to use calories instead here is the formula for mass of the coffee without substituting in values.
if the silver spoon placed in the coffee in exercisE 6 (tHE QUESTION BEFORE THIS) causes it to...
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