Question 10
Phone bills for residents of Shangri-La are normally distributed, with a mean of 98.75 gold coins and a standard deviation of 10.21 gold coins. Random samples of 48 phone bills are drawn from the population and the mean of each sample is determined. Find the mean of the indicated sampling distribution.
Round to the ten-thousandths place (4 decimal places), as needed.
State the answer only and no additional work.
Solution :
Given that ,
mean = =98.75
standard deviation = = 10.21
n = 48
sample distribution of sample mean is ,
=
= 98.75
Question 10 Phone bills for residents of Shangri-La are normally distributed, with a mean of 98.75...
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