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Turn in TWO original queries using MySQL and the output from the queries with the follow...

Turn in TWO original queries using MySQL and the output from the queries with the follow requirements:

1) two or more joined tables

2) 6 or more attributes

3) Nested select OR having OR group by

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Answer #1

Let's look at a selection from the "Orders" table:

OrderID CustomerID OrderDate
10308 2 1996-09-18
10309 37 1996-09-19
10310 77 1996-09-20

Then, look at a selection from the "Customers" table:

CustomerID CustomerName ContactName Country
1 Alfreds Futterkiste Maria Anders Germany
2 Ana Trujillo Emparedados y helados Ana Trujillo Mexico
3 Antonio Moreno Taquería Antonio Moreno Mexico

1) QUERY:

SELECT Orders.OrderID, Customers.CustomerName, Orders.OrderDate
FROM Orders
INNER JOIN Customers ON Orders.CustomerID=Customers.CustomerID;

OUTPUT:

OrderID CustomerName OrderDate
10308 Ana Trujillo Emparedados y helados 9/18/1996
10365 Antonio Moreno Taquería 11/27/1996
10383 Around the Horn 12/16/1996
10355 Around the Horn 11/15/1996
10278 Berglunds snabbköp 8/12/1996

2) QUERY:

SELECT CustomerID, CustomerName, ContactName, Address, City, Country FROM Customers;

OUTPUT:

CustomerID CustomerName ContactName Address City Country
1 Alfreds Futterkiste Maria Anders Obere Str. 57 Berlin Germany
2 Ana Trujillo Emparedados y helados Ana Trujillo Avda. de la Constitución 2222 México D.F. Mexico
3 Antonio Moreno Taquería Antonio Moreno Mataderos 2312 México D.F. Mexico
4 Around the Horn Thomas Hardy 120 Hanover Sq. London UK
5 Berglunds snabbköp Christina Berglund Berguvsvägen 8 Luleå Sweden
6 Blauer See Delikatessen Hanna Moos Forsterstr. 57 Mannheim Germany
7 Blondel père et fils Frédérique Citeaux 24, place Kléber Strasbourg France
8 Bólido Comidas preparadas Martín Sommer C/ Araquil, 67 Madrid Spain
9 Bon app' Laurence Lebihans 12, rue des Bouchers Marseille France
10 Bottom-Dollar Marketse Elizabeth Lincoln 23 Tsawassen Blvd. Tsawassen Canada

3)

Consider the CUSTOMERS table having the following records −

+----+----------+-----+-----------+----------+
| ID | NAME     | AGE | ADDRESS   | SALARY   |
+----+----------+-----+-----------+----------+
|  1 | Ramesh   |  35 | Ahmedabad |  2000.00 |
|  2 | Khilan   |  25 | Delhi     |  1500.00 |
|  3 | kaushik  |  23 | Kota      |  2000.00 |
|  4 | Chaitali |  25 | Mumbai    |  6500.00 |
|  5 | Hardik   |  27 | Bhopal    |  8500.00 |
|  6 | Komal    |  22 | MP        |  4500.00 |
|  7 | Muffy    |  24 | Indore    | 10000.00 |
+----+----------+-----+-----------+----------+

Now, let us check the following subquery with a SELECT statement.

SQL> SELECT * 
   FROM CUSTOMERS 
   WHERE ID IN (SELECT ID 
         FROM CUSTOMERS 
         WHERE SALARY > 4500) ;

This would produce the following result.

+----+----------+-----+---------+----------+
| ID | NAME     | AGE | ADDRESS | SALARY   |
+----+----------+-----+---------+----------+
|  4 | Chaitali |  25 | Mumbai  |  6500.00 |
|  5 | Hardik   |  27 | Bhopal  |  8500.00 |
|  7 | Muffy    |  24 | Indore  | 10000.00 |
+----+----------+-----+---------+----------+
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