A manufacturer knows that their items have a normally
distributed lifespan, with a mean of 14.9 years, and standard
deviation of 2.1 years.
If you randomly purchase one item, what is the probability it will
last longer than 19 years?
Solution :
Given that ,
mean = = 14.9
standard deviation = = 2.1
P(x > 19) = 1 - P(x < 19)
= 1 - P[(x - ) / < (19 - 14.9) / 2.1)
= 1 - P(z < 1.9524)
= 1 - 0.9746
= 0.0254
Probability = 0.0254
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