A 22.8 kg box is placed at the bottom of a 39.7° ramp whose surface is...
A 22.8 kg box is placed at the bottom of a 39.7° ramp whose surface is rough enough that the coefficient of kinetic friction is 0.222. You push on the box parallel to the ramp's surface, so that the box accelerates up the ramp at 0.911 m/s2. What must be the force (in N) supplied by you?
Homework Answers
considering equilibrium of forces along the ramp
ma = F - mg sin x - u mg cos x
22.8 * 0.911 = F - 22.8 * 9.8* sin 39.7 - 0.222* 22.8* 9.8* cos 39.7
F = 201.662 N
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