Question

Change your C++ average temperatures program to:

• In a non range-based loop
  • Prompt the user for 5 temperatures.
  • Store them in an array called temperatures.
• Use a Range-Based loop to find the average.
• Print the average to the console using two decimals of precision.
• Do not use any magic numbers.

#include<iostream>
using namespace std;
void averageTemperature() // function definition starts here
{
   float avg; // variable declaration
   int num,sum=0,count=0; /* 'count' is the int accumulator for number of temperatures, 'num' is the int accumulator for storing temperature*/
   cout<<"Enter temperatures to calculate the average (enter -999 to stop):";
   while(cin>>num) // reading the integer input from the keyboard and storing in 'num'
   {
       if(num!=-999) // if 'num' is not -999
       {
           sum += num; // performs the sum
           count++; // increments the count of the temperatures
       }
       else // if 'num' is -999
           break; // jumps out of while loop
   }
   avg = (float)sum/count; // calculating the average of temperatures
   cout<<"The average temperature is:"<<avg;   // displaying the average temperature
}
int main()
{
   averageTemperature(); // function call
   return 0;
}

Answer 1

#include <iostream>
using namespace std;

void averageTemperature() // function definition starts here
{
float avg; // variable declaration
int temp[5],sum=0,num; // 'num' is the int accumulator for storing temperature

cout<<"Enter 5 temperatures to calculate the average : ";

for (int i = 0; i < 5; i++) // non range-based loop
{
cin >> temp[i]; // reading the integer input from the keyboard and storing in temp
sum += temp[i]; // performs the sum
}

for (int num : temp) // Range-based loop
sum += num;

avg = (float)sum/5; // calculating the average of temperatures
cout<<"The average temperature is:"<<avg; // displaying the average temperature
}
int main()
{
averageTemperature(); // function call
return 0;
}