You found a mean =110 and standard deviation=20 in a sample of n=40 . A range that you are 95% certain contains the population mean is...
Solution:
Given in the question
Mean = 110
Standard deviation = 20
No. of sample = 40
alpha = 0.05, alpha/2 = 0.025 and talpha/2 = 2.02 from t table at
df=39
So 95% confidence interval is
mean +/- talpha/2*sd/sqrt(n)
110 +/- 2.02*20/sqrt(40)
110 +/- 6.39
So 95% confidence interval is
103.61 to 116.39
You found a mean =110 and standard deviation=20 in a sample of n=40 . A range...
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