A 10-gram bullet is launched with a muzzle velocity of 850 m/s. It is fired from a 308 Winchester with a WEIGHT of 7 pounds. What is the recoil velocity of the weapon?
Data in the question given as:
Mass of the weapon , Mw=> 7 pounds = 3.2 Kg
Mass of the bullet, MB = 10 g = 0.010 Kg
muzzle velocity of the bullet ( which is the velocity with which the bullet leaves the weapon) , VB= 850 m/s
Recoil velocity of the weapon , Vw = ?
therefore , here we can apply conservation of linear momentum principle and by which we can calculate the recoil velocity of the weapon.
∴ MwVw + MBVB = 0
so, 3.2 *Vw + 0.01 *850 = 0
∴ Vw = -(850* 0.01) /3.2
= - 2.656 m/s (answer)
so finally the recoil velocity of the weapon is - 2.656 m/s
moreover the recoil velocity of the weapon is negative as it is opposite in direction of the bullet's velocity.
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