The conjugate acid of ethanol amine (HOCH2CH2NH3+) has pKa = 9.50. What can you conclude about...
The conjugate acid of ethanol amine (HOCH2CH2NH3+) has pKa = 9.50. What can you conclude about a solution of this amine in which [RNH3+)] = 10 x [RNH2]?)
Question 9 options:
a) pH = 10.50
b) pH = 9.50
c) pH = 8.50
d) None of the above.
Homework Answers
It is basic buffer
pKb = 14-9.50 = 4.5
pOH = pKb + log([RNH3+]/[RNH2])
= 4.5+log(10/1)
= 5.5
pH = 14-5.5 = > 8.50
(c) is correct option.
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