Question

A professor has constructed a 3-by-4 two-dimensional array of float numbers. This array currently contains the lab grades, quiz grades and exam grades of three students in the professor’s class. Write a C++ program that calculate the final grade for each student and save it to the last column. You program should display the following output: Lab Quiz ExamFinal Student 1 ## ## ## ## Student 2 ## ## ## ## Student 3 ## ## ## ## The final grade consists of 30% lab grade, 30% quiz grade and 40% exam. For example, if lab grade is 95, quiz grade is 82 and exam grade is 87, the final grade is equal to 95∗0.3+82∗0.3+87∗0.4. Use random numbers between 40 and 100 for lab, quiz and exam grades.

Answer 1

C++ CODE :-
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
float a[3][4] = {
{95, 82, 87, 0} , /* initializers for row indexed by 0 */
{96, 85, 86, 0} , /* initializers for row indexed by 1 */
{42, 55, 63, 0} /* initializers for row indexed by 2 */
};                        // 4th elements should be calculated
const char separator = ' '; // declaring constants for output allignment
const int nameWidth = 19;
const int numWidth = 18;
cout << right << setw(27) << setfill(separator) << "Lab"; // display table headings
cout << right << setw(nameWidth) << setfill(separator) << "Quiz";
cout << right << setw(nameWidth) << setfill(separator) << "Exam";
cout << right << setw(nameWidth) << setfill(separator) << "Final"<<endl;

for(int i=0;i<3;i++) // outer loop on rows
{
for(int j=0;j<3;j++) // inner loop on coloumns
{
if(j==0 || j==1) // if grades from lab or quiz ,dhould multiply with 0.3 i.e; 30%
{
a[i][j] = 0.3 * a[i][j];
}
else
a[i][j] = 0.4 * a[i][j]; // if grade from exam ,dhould multiply with 0.4 i.e; 40%

a[i][3] = a[i][3] + a[i][j]; // computing 4th element ie; final
}
}
for(int i=0;i<3;i++) // display scores in table format
{
cout <<left << setfill(separator) << "student :"<<(i+1) ;
for(int j=0;j<4;j++)
{
cout << right << setw(numWidth) << setfill(separator) << a[i][j];
}
cout<<endl;
}
cout << endl;
return 0;
}

OUTPUT :-