how you could obtain undrained cohesion using the unconfined compression and unconsolidated undrained tests
how you could obtain undrained cohesion using the unconfined compression and unconsolidated undrained tests
Homework Answers
DRAINED-UNDRAINED STRENGTH: The Drained-Undrained strength option is to define Material Properties.
- It means to define a soil strength envelope which considers both drained and undrained Mohr-Coulomb strength parameters. The shear strength is defined in terms of effective stress parameters c’ and phi’, up to a maximum value of shear strength defined by the undrained cohesion Cu.
If the cohesion is variable with depth:
- Select the "Cohesion varies with depth" checkbox in the Define Material Properties
- This will enable the Define button. Select the Define button, and you will see another, in which you can define the drained or undrained cohesion as a function of depth.
- Undrained Strength Parameters: By default, the (Undrained) Cohesion Type = F(Depth) and the (Drained) Cohesion Type = F(undrained Cu)
- Constant
- F(Depth from Top of Layer)
- F(Depth from Horizontal )
- F(Distance to Slope)
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how you could obtain undrained cohesion using the
unconfined compression and unconsolidated undrained tests
3. Data from Unconfined Compression tests on two samples of the same soil is shown in...
3. Data from Unconfined Compression tests on two samples of the same soil is shown in Table 3 below. One of the two samples is an undisturbed sample and the other is remolded. The soil samples were 1.18in in diameter and 3.00in height. Table 3: Results from Unconfined Compression Strength Test Axia Cross Sec Axial Deform (inStrain Area Undisturbe Remolded Undisturbe Remolded Axial Load (lb Axial Stress (psi coIT 0 0.06 0.12 0.18 0.24 0.30 0.36 0.42 0.48 0.54 0.60...
Q2: A normally consolidated clay sample is tested under uniaxial (unconfined) compession. Unconfined compressive strength was...
Q2: A normally consolidated clay sample is tested under uniaxial (unconfined) compession. Unconfined compressive strength was found as qu=1.80 kg/cm². It is known from previous drained triaxial tests that, '=30°. A) What would be the pore pressure at failure durin unconfined testing?, B) Without changing water content, if you carry out an unconsolidated-undrained triaxial test on the same sample, calculate maximum principle stres values for 0;= 3 kg/cm², 03= 3.5 kg/cm², 0;= 4 kg/cm².
Question 1 Consolidated undrained triaxial laboratory tests yielded the following results: Additional axial stress at Cell...
Question 1 Consolidated undrained triaxial laboratory tests yielded the following results: Additional axial stress at Cell pressure Pore water failure (kN/m2) pressure at failure (kN/m²) (kN/m²) 200 650 400 770 880 350 50 600 a. Draw the Mohr circles representing: i. Total stresses ii. Effective stresses b. From the Mohr circles, determine the cohesion and angle of internal friction for the two scenarios in a) above c. Briefly differentiate between consolidated drained (CD) and unconsolidated undrained (UU) triaxial tests. Indicate...
Q3. Vane shear tests were conducted in layer of soft clay. The vane dimensions were 63.5...
Q3. Vane shear tests were conducted in layer of soft clay. The vane dimensions were 63.5 mm (D)x 127 mm (H). At a certain depth, the torque required to cause a failure was 0.051 kN.m. The liquid limit of the clay was 56 and the plastic limit was 23. Estimate the undrained cohesion, c of the clay for use in the design by applying Bjerrum's λ relationship given below. Investigate about what is Bjerrum's relationship: 1.7-0.54 log[PI(%)] Discuss when you...
Problem 3 (10 points):A set of three drained triaxial compression tests is performed on a uniformly...
Problem 3 (10 points):A set of three drained triaxial compression tests is performed on a uniformly graded angular sand. The major and minor principal stresses at the beginning (σ1c and ơ3c) sand end of the tests (c'lf and ơ'3r) are provided in the table below. The end of the test corresponds to a failure condition in the soil. Draw Mohr circles for each test, and plot the failure envelope. σ'sc (kPa) 50 100 200 o'e (kPa) 50 100 200 σ'3f...
3. Shear strength measurements derived from unconfined compression tests for two types of soils gave the...
3. Shear strength measurements derived from unconfined compression tests for two types of soils gave the results shown in the following table (measured in tons per square foot). Math 1P98 Spring 2020 Assignment #2 Due Friday, June 26, 2020 Soil Type 1 Soil Type 2 ni = 31 n2 = 35 21 = 1.56 T2 = 1.47 81 = 0.24 82 = 0.21 (a) Do the soils appear to differ with respect to mean shear strength? Use the critical value...
help! 6. Shear strength measurements derived from unconfined compression tests for two types of soils gave...
help!
6. Shear strength measurements derived from unconfined compression tests for two types of soils gave the results shown in the following table (measurements in tons per square foot) Soil Type I Soil Type I n1 30 X1 1.65 X2 = 1.43 81=0.26 s2 = 0.22 Note) T-table does not carry all possible values for degrees of freed of freedom that you are looking for, you can take the closest degree of freedom. For example, if you need to use...
1. During an unconfined compression test on a stabilized petroleum sludge, the following data were obtained....
1. During an unconfined compression test on a stabilized petroleum sludge, the following data were obtained. (a) Plot the stress-strain relationship and determine the unconfined compressive strength (USE MS EXCEL). Note that the original sample length was 20 cm and the original sample diameter was 9.1 cm. (b) How many samples could be put vertically without causing a failure problem to the bottom (the first) solidified sample? Load (kg) 0 510 900 1370 1900 2490 3100 3630 3990 4190 4330...
ANSWER ALL QUESO uestion 1: (10 marks) tate the correct answer (True or False) in your...
ANSWER ALL QUESO uestion 1: (10 marks) tate the correct answer (True or False) in your ANSWER BOOK along with the Question number, lave all your answers for Question 1 at one place 1 The angle of internal friction of normally consolidated clay determined fromTF consolidated drained triaxial shear tests is higher in comparison to the angle of internal friction value determined from consolidated undrained tests without pore- water pressure measurements. 42%) is the same t F At liquid limit...
properties of alcohol 5. Using the tests performed in this experiment, how could you distinguish between...
properties of alcohol
5. Using the tests performed in this experiment, how could you distinguish between the following pairs of compounds? Tell what reagent or test you would use and what you would observe. 1-Butanol and 2-butanol a) b) C Isobutyl alcohol and tert-butyl alcohol 1-Propanol and 1-heptanol Cyclohexanol and cyclohexane d)
3. Data from Unconfined Compression tests on two samples of the same soil is shown in Table 3 below. One of the two samples is an undisturbed sample and the other is remolded. The soil samples were 1.18in in diameter and 3.00in height. Table 3: Results from Unconfined Compression Strength Test Axia Cross Sec Axial Deform (inStrain Area Undisturbe Remolded Undisturbe Remolded Axial Load (lb Axial Stress (psi coIT 0 0.06 0.12 0.18 0.24 0.30 0.36 0.42 0.48 0.54 0.60...
Q2: A normally consolidated clay sample is tested under uniaxial (unconfined) compession. Unconfined compressive strength was found as qu=1.80 kg/cm². It is known from previous drained triaxial tests that, '=30°. A) What would be the pore pressure at failure durin unconfined testing?, B) Without changing water content, if you carry out an unconsolidated-undrained triaxial test on the same sample, calculate maximum principle stres values for 0;= 3 kg/cm², 03= 3.5 kg/cm², 0;= 4 kg/cm².
Question 1 Consolidated undrained triaxial laboratory tests yielded the following results: Additional axial stress at Cell pressure Pore water failure (kN/m2) pressure at failure (kN/m²) (kN/m²) 200 650 400 770 880 350 50 600 a. Draw the Mohr circles representing: i. Total stresses ii. Effective stresses b. From the Mohr circles, determine the cohesion and angle of internal friction for the two scenarios in a) above c. Briefly differentiate between consolidated drained (CD) and unconsolidated undrained (UU) triaxial tests. Indicate...
Q3. Vane shear tests were conducted in layer of soft clay. The vane dimensions were 63.5 mm (D)x 127 mm (H). At a certain depth, the torque required to cause a failure was 0.051 kN.m. The liquid limit of the clay was 56 and the plastic limit was 23. Estimate the undrained cohesion, c of the clay for use in the design by applying Bjerrum's λ relationship given below. Investigate about what is Bjerrum's relationship: 1.7-0.54 log[PI(%)] Discuss when you...
Problem 3 (10 points):A set of three drained triaxial compression tests is performed on a uniformly graded angular sand. The major and minor principal stresses at the beginning (σ1c and ơ3c) sand end of the tests (c'lf and ơ'3r) are provided in the table below. The end of the test corresponds to a failure condition in the soil. Draw Mohr circles for each test, and plot the failure envelope. σ'sc (kPa) 50 100 200 o'e (kPa) 50 100 200 σ'3f...
3. Shear strength measurements derived from unconfined compression tests for two types of soils gave the results shown in the following table (measured in tons per square foot). Math 1P98 Spring 2020 Assignment #2 Due Friday, June 26, 2020 Soil Type 1 Soil Type 2 ni = 31 n2 = 35 21 = 1.56 T2 = 1.47 81 = 0.24 82 = 0.21 (a) Do the soils appear to differ with respect to mean shear strength? Use the critical value...
help!
6. Shear strength measurements derived from unconfined compression tests for two types of soils gave the results shown in the following table (measurements in tons per square foot) Soil Type I Soil Type I n1 30 X1 1.65 X2 = 1.43 81=0.26 s2 = 0.22 Note) T-table does not carry all possible values for degrees of freed of freedom that you are looking for, you can take the closest degree of freedom. For example, if you need to use...
1. During an unconfined compression test on a stabilized petroleum sludge, the following data were obtained. (a) Plot the stress-strain relationship and determine the unconfined compressive strength (USE MS EXCEL). Note that the original sample length was 20 cm and the original sample diameter was 9.1 cm. (b) How many samples could be put vertically without causing a failure problem to the bottom (the first) solidified sample? Load (kg) 0 510 900 1370 1900 2490 3100 3630 3990 4190 4330...
ANSWER ALL QUESO uestion 1: (10 marks) tate the correct answer (True or False) in your ANSWER BOOK along with the Question number, lave all your answers for Question 1 at one place 1 The angle of internal friction of normally consolidated clay determined fromTF consolidated drained triaxial shear tests is higher in comparison to the angle of internal friction value determined from consolidated undrained tests without pore- water pressure measurements. 42%) is the same t F At liquid limit...
properties of alcohol
5. Using the tests performed in this experiment, how could you distinguish between the following pairs of compounds? Tell what reagent or test you would use and what you would observe. 1-Butanol and 2-butanol a) b) C Isobutyl alcohol and tert-butyl alcohol 1-Propanol and 1-heptanol Cyclohexanol and cyclohexane d)
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