How many moles of sucrose are contained in a 0.5 L
solution of 0.32 M sucrose?
Ans :- 0.16 mol
Explanation :-
We know that,
Molarity = Number of moles / Volume of the solution in L
So,
Number of moles of Sucrose = Molarity x Volume of solution in L
= 0.32 M x 0.5 L
= 0.16 mol
Hence, Number of moles of Sucrose = 0.16 mol
How many moles of sucrose are contained in a 0.5 L solution of 0.32 M sucrose?
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