19.25 grams of acetic acid solution (density = 1.00g/mL) required 18.05mL of 0.875M sodium hydroxide solution to reach the endpoint of a titration. Using this data, the acetic acid would have a concentration of
Answer :-
To find the Molarity of the acetic acid in the vinegar sample first moles of acetic acid aee calculated then Molarity is calculated.
The answer is given in the image,
19.25 grams of acetic acid solution (density = 1.00g/mL) required 18.05mL of 0.875M sodium hydroxide solution...
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