What is the enthalpy of condensation,in kJ/mol,of bromine whose B. P. is +58.8oC, if 16.2 kJ of heat is required to vaporize 86.3 g of bromine
Answer
∆Hcond = -30 kJ/mol
Explanation
Mass of bromine = 86.3g
Molar mass of bromine = 159.81g/mol
Number of moles of bromine = 86.3g/159.81g/mol = 0.5400mol
Enthalphy of vaporization at b.p = (16.2kJ/0.5400ml)×1mol = 30kJ/mol
Enthalphy of condenzation(∆Hcond) = -Enthalphy of vaporuzation(∆Hvap)
∆Hcond = - 30kJ/mol
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