Use mass-to-mass stoichiometry, calculate the theoretical yield of NaCl in reaction NaHCO3+HCl —> NaCl+ H2O+CO2 obtained...

Question

Question

Use mass-to-mass stoichiometry, calculate the theoretical yield of NaCl in reaction

NaHCO3+HCl —> NaCl+ H2O+CO2

obtained mass of NaHCO3 0.372 grams

mass of NaCl got from the reaction 0.148 grams

Answer 1

Answer #1

Given the mass of NaHCO₃ = 0.372 g

=> Moles of NaHCO₃ = mass/molar mass = 0.372 g / 84.007 g/mol = 0.0044282 mol

Since the coefficient of both NaHCO₃ and NaCl are 1, the mole ratio is also 1:1

=> Moles of NaCl formed = 0.0044282 mol NaHCO₃ * (1 mol NaCl / 1 mol NaHCO₃) = 0.0044282 mol NaCl

=> Mass of NaCl formed = mol * molar mass of NaCl = 0.0044282 mol * 58.44 g/mol = 0.259 g

Hence theoretical yield of NaCl = 0.259 g (Answer)

Answer 2

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