an object height=0.4m is placed 0.1m in front of a lense. the lense power is 5...
an object height=0.4m is placed 0.1m in front of a
lense. the lense power is 5 D
what is distance from lense to image
what is height of image
is image real or virtual? inverted or not
Homework Answers
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an object height=0.4m is placed 0.1m in front of a
lense. the lense power is 5...
A 4 mm high object is placed 5 cm in front of a concave mirror with...
A 4 mm high object is placed 5 cm in front of a concave mirror with a radius of curvature 20 cm. 1)The image distance is: Between -15 cm and zero Less than -15 cm Greater than 15 cm Between 0 and 15 cm 2) The magnitude of the image height will be: Less than 3 mm Between 3 and 6 mm Greater than 9 mm Between 6 and 9 mm 3) The image will be: Virtual and inverted Real...
1.) An object is placed in front of a diverging lens with a focal length of...
1.) An object is placed in front of a diverging lens with a focal length of 17.7 cm. For each object distance, find the image distance and the magnification. Describe each image. (a) 35.4 cm location _____cm magnification _____ nature real virtual upright inverted (b) 17.7 cm location _____ cm magnification _____ nature real virtual upright inverted (c) 8.85 cm location _____ cm magnification _____ nature real virtual upright inverted 2.) An object is placed in front of a converging lens...
D Question 15 1 pts A4 mm high object is placed 5 cm in front of...
D Question 15 1 pts A4 mm high object is placed 5 cm in front of a concave mirror with radius of curvature 20 cm. Questions 13-15 refer to this situation. Time Attem 1 Hou The image will be: Virtual and upright Real and inverted Real and upright Virtual and Inverted Question 16 1 pts A4 mm high object is placed 9 cm in front of a convex mirror with radius of curvature 12 cm. Questions 16-18 refer to this...
An object is placed 50.0cm in front of a lens. The image forms on the same...
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O inverted, diverging, positive, real upright, converging, positive, virtual inverted, converging, positive, virtual upright, converging, positive, real upright, converging, negative, virtual upright, converging, negative, real inverted, converging, positive, real O inverted, diverging, negative, real
An object is placed 50.0cm in front of a lens. The image forms on the same...
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O upright, converging, positive, virtual O inverted, converging, positive, real inverted, diverging, negative, real O upright, converging, negative, virtual O inverted, diverging, positive, real O inverted, converging, positive, virtual O upright, converging, positive, real O...
(5%) Problem 3: An object is placed between the focal point and the front of a...
(5%) Problem 3: An object is placed between the focal point and the front of a concave mirror, as shown. The focal-point locations are indicated by the small black circles. 50% Part (a) Which diagram best represents the image location and magnification for the original object? E 는 1 O - A 50% Part (b) Which choice best describes the image? The image is virtual, upright, and smaller than the object. The image is virtual, inverted, and smaller than the...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) upright, converging, negative, real inverted, converging, positive, virtual upright, converging, negative, virtual upright, converging, positive, virtual upright, converging, positive, real O inverted, converging, positive, real inverted, diverging, positive, real inverted, diverging,...
An object is placed 24.1 cm in front of a convex mirror of focal length 50...
An object is placed 24.1 cm in front of a convex mirror of focal length 50 cm. Note: Do convex mirrors have a positive or negative focal length? What is its image position? Answer in units of cm. The magnification of the image in the previ- ous question is: With the arrangement discussed above, the image is: 1. virtual, inverted, smaller than object 2. real, erect, smaller than object 3. real, inverted, bigger than object 4. real, erect, bigger than...
A lense has a focal length of -10 cm. If the object distance is 5 cm...
A lense has a focal length of -10 cm. If the object distance is 5 cm then the image will be A. Inverted and real B. Upright and imaginary C. Upright and real D. Inverted and Imaginary
An object of height 1 cm is located at a distance 30 cm in front of...
An object of height 1 cm is located at a distance 30 cm in front of a concave mirror of focal length 10 cm. (a) What is the radius of curvature of the mirror? (b) Where is the image located? (c) Is the image real or virtual? (d) What is the magnification of the mirror? (e) Is the image enlarged or reduced? (f) What is the height of the image? (g) Is the image erect or inverted?
D Question 15 1 pts A4 mm high object is placed 5 cm in front of a concave mirror with radius of curvature 20 cm. Questions 13-15 refer to this situation. Time Attem 1 Hou The image will be: Virtual and upright Real and inverted Real and upright Virtual and Inverted Question 16 1 pts A4 mm high object is placed 9 cm in front of a convex mirror with radius of curvature 12 cm. Questions 16-18 refer to this...
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O inverted, diverging, positive, real upright, converging, positive, virtual inverted, converging, positive, virtual upright, converging, positive, real upright, converging, negative, virtual upright, converging, negative, real inverted, converging, positive, real O inverted, diverging, negative, real
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O upright, converging, positive, virtual O inverted, converging, positive, real inverted, diverging, negative, real O upright, converging, negative, virtual O inverted, diverging, positive, real O inverted, converging, positive, virtual O upright, converging, positive, real O...
(5%) Problem 3: An object is placed between the focal point and the front of a concave mirror, as shown. The focal-point locations are indicated by the small black circles. 50% Part (a) Which diagram best represents the image location and magnification for the original object? E 는 1 O - A 50% Part (b) Which choice best describes the image? The image is virtual, upright, and smaller than the object. The image is virtual, inverted, and smaller than the...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) upright, converging, negative, real inverted, converging, positive, virtual upright, converging, negative, virtual upright, converging, positive, virtual upright, converging, positive, real O inverted, converging, positive, real inverted, diverging, positive, real inverted, diverging,...
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