0.665 grams of a soluble monoprotic acid powder are added to enough water to make 40mL of solution. The solution is then titrated with 0.2M NaOH. The volume of NaOH used in the titration 15.75 mL. What is the molar mass of the soluble acid?
0.665 grams of a soluble monoprotic acid powder are added to enough water to make 40mL...
A 0.699 g sample of a monoprotic acid is dissolved in water and titrated with 0.240 M NaOH. What is the molar mass of the acid if 30.0 mL of the NaOH solution is required to neutralize the sample? molar mass: g/mol
A 0.173 g sample of a monoprotic acid is dissolved in water and titrated with 0.120 M NaOH. What is the molar mass of the acid if 10.5 mL of the NaOH solution is required to neutralize the sample? molar mass: 274.6 molar mass: 274.6 g/mol g/mol
An analytical chemist weighs out 1.300 grams of an unknown monoprotic acid into a 250 mL volumetric flask and dilutes to the mark. The chemist then obtains 100 mL of the solution and titrates the 100mL of the solution with 0.1 M NaOH. When the titration reaches the equivalence point, the chemist finds he has added 24.50 mL of NaOH solution. Calculate the molar mass of the unknown
A 1.05 g sample of a monoprotic acid is dissolved in water and titrated with 0.320 M NaOH. What is the molar mass of the acid if 19.0 mL of the NaOH solution is required to neutralize the sample? molar mass: molar mass: 8/mol g/mol about us can
A 0.782 g sample of a monoprotic acid is dissolved in water and titrated with 0.320 M NaOH. What is the molar mass of the acid if 13.5 mL of the NaOH solution is required to neutralize the sample?
5.00 mL of a solution containing a monoprotic acid was placed in a 100-mL volumetric flask, diluted to the mark with deionized water and mixed well. Then, 25.00 mL of this diluted acid solution was titrated with 0.08765 M NaOH. 9.23 mL of NaOH was required to reach the endpoint. a. What does the term monoprotic mean? b. Determine the molar ratio between the acid and NaOH. c. Calculate the moles of NaOH used in this titration. d. Calculate the...
2. A 0.500-gram sample of a weak, nonvolatile monoprotic acid, HA, was dissolved in sufficient water to make 50.0 milliliters of solution. The solution was then titrated with a standard NaOH solution. Predict how the calculated molar mass of HA would be affected (too high, too low, or not affected) by the following laboratory procedures. Explain each of your answers. A. (2 points.). After rinsing the buret with distilled water, the buret is filled with the standard NaOH solution; the...
A sample of 0.2140 grams of an unknown monoprotic weak acid was dissolved in 25.0mL of water and titrated with 0.0950M NaOH. The acid required 15.50mL of NaOH to reach the equivalence point. What is the molar mass of the unknown acid?
Titration of a Weak Monoprotic Acid with a Strong Base Volume of Base (mL) 1. Using the graph, determine the K, of the weak acid. 2. Suppose 100mL of the monoprotic acid referred to in the graph was titrated with 1M NaOH, determine the molarity of the weak acid. The corresponding balanced chemical equation is shown below. HA + NaOH + H2O + A + Nat 3. If the weak acid above was prepared by using 5g of the weak...
Determine the molar mass monoprotic acid used in the experiment from the following data obtained during the course of this experiment a) 40mL of pre prepared 3.0g/L of an unknown monoprotic acid in a 100mL beaker for titration with NaOH using the pH meter b) Molarity of NaOH Mb= 0.0768moles/L determined by titration with known strength of khp c) Volume of NaOH to equivalence point = 23.5mL