in a time use study, 20 randomly selected managers were found to spend a mean if 2.25 hours each day on paperwork. the standard deviation of the 20 scores is s =1.7 hours. construct he 98% confidence Interval for the population standard deviation. use x2- distribution for analysis.
in a time use study, 20 randomly selected managers were found to spend a mean if...
In a certain management study, 15 randomly selected managers were found to spend a mean of 2.40 hours each day on paperwork with a standard deviation of 1.30 hours. Construct a 90% Confidence Interval for the mean time spent on paperwork by all managers. State the meaning of the interval in the context of the problem. Use the given data to construct a confidence interval at the requested level: x = 125, n = 317, confidence level 95% (Hint: Refer...
IX 3 In a certain management study, 15 randomly selected managers were found to spend a mean of 2.40 hours each day on paperwork with a standard deviation of 1.30 hours. a. Construct a 90% Confidence Interval for the mean time spent on paperwork by all managers. b. State the meaning of the interval in the context of the problem. X Use the given data to construct a confidence interval at the requested level: x = 125, n = 317,...
H-80.2 B)69.3 < μ < 79.7 C) 70.5 < μ < 79.5 12. In a time-use study, 20 randomly selected managers were found to spend a mean of 2.4 hours each day on paperwork. The standard deviation of the 20 scores is s 1.3 D) 67.7 < μ < 84.7 ours. Construct the 95% confidence interval for the population standard deviation σ (Use y -distribution for analysis). Provide estimates and circle one of the multiple choice answers. (6 points) A)...
A study of women’s weights found that a randomly selected sample of 150 women had a mean weight of 147.3 lb. Assuming that the population standard deviation is 19.6 lb., construct a 95% confidence interval estimate of the mean weight of all women. Choose the correct interval from below: Choose one • 10 points (144.211, 150.389) (140.611, 146.789) (144.667, 149.933) (144.163, 150.437)
The mean bill of 16 randomly selected customers in a restaurant is found to be $32, with a standard deviation of $3.50. Construct a 99% confidence interval for the mean bill of a customer.
The thicknesses of 55 randomly selected ceramic tiles were found to have a variance of 3.18 Construct the 98% confidence interval for the population variance of the thicknesses of all ceramic tiles in this factory. Round your answers to two decimal places.
A recent study of 3000 children randomly selected found 23% of them deficient in vitamin D. a) Construct the 98% confidence interval for the true proportion of children who are deficient in vitamin D. left parenthesis nothing comma nothing right parenthesis (Round to three decimal places as needed.) b) Explain carefully what the interval means. A. We are 98% confident that the interval contains the true proportion of children deficient in vitamin D. B. We are 98% confident that the...
years. A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.84 years and the standard deviation is 8.84 25 39 43 25 42p a) Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 23 28 42 45 31 interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed...
33 46 48 21 30 32 10 31 20 29 A survey of 25 randomly selected customers found the ages shown (in years). The mean is 31.76 years and the standard deviation is 10.37 years. a) Construct a 98 % confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 20 38 40 35 40 interval have been met. 22 37 10 41 26 b) How large is the margin of error?...
Question 4 23 potatoes are randomly selected and measured; the sample mean is found to be 210 g and the sample standard deviation is found to be 21.3 g. Build an upper-bounded 95% confidence interval for the population standard deviation. (Juo %56) 811'8Z>D SO'O = (zz'DE ZI)PZ!y:JamSuy