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Question 4 23 potatoes are randomly selected and measured; the sample mean is found to be 210 g and the sample standard devia

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C2954 -0.95 .na23, = 2109S = 2103 g X = 1-0.95 -0.05 x/2 200025 23-122 = 10.9823 We 10.025, 22 - 95% variance confidence uppe

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