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Question 1. The pH of 20 randomly selected lakes is measured. Their average pH is 5.7. Part A. Historically the standard devi

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Answer #1

i) M = 5.7
Z critical = 1.96
sM = √(0.92/20) = 0.2

μ = M ± Z(sM)
μ = 5.7 ± 1.96*0.2
μ = 5.7 ± 0.392

95% CI [5.308, 6.092].

You can be 95% confident that the population mean (μ) falls between 5.308 and 6.092.

ii) Z critical = 1.64
sM = √(0.9^2/20) = 0.2

μ = M ± Z(sM)
μ = 5.7 ± 1.64*0.2
μ = 5.7 ± 0.328
90% CI [5.372, 6.028].

You can be 90% confident that the population mean (μ) falls between 5.372 and 6.028.

iii) Z critical = 1.28
sM = √(0.9^2/20) = 0.2

μ = M ± Z(sM)
μ = 5.7 ± 1.28*0.2
μ = 5.7 ± 0.256
80% CI [5.444, 5.956].

You can be 80% confident that the population mean (μ) falls between 5.444and 5.956

iv) The width increases as the confidence level increases. Confidence level changing the width of confidence interval.

Note: As per the Q&A guidelines I have done the first four please repost the rest. Thank You


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