According to the following reaction, how many grams of
ammonia will be formed upon the complete reaction
of 24.0 grams of ammonium
chloride?
ammonium chloride (aq) =
ammonia (g) +
hydrochloric acid (aq)
grams ammonia
Molar mass of NH4Cl,
MM = 1*MM(N) + 4*MM(H) + 1*MM(Cl)
= 1*14.01 + 4*1.008 + 1*35.45
= 53.492 g/mol
mass of NH4Cl = 24 g
mol of NH4Cl = (mass)/(molar mass)
= 24/53.49
= 0.4487 mol
Balanced chemical equation is:
1NH4Cl ---> 1NH3 + 1HCl
According to balanced equation
mol of NH3 formed = moles of NH4Cl
= 0.4487 mol
Molar mass of NH3,
MM = 1*MM(N) + 3*MM(H)
= 1*14.01 + 3*1.008
= 17.034 g/mol
mass of NH3 = number of mol * molar mass
= 0.4487*17.03
= 7.643 g
Answer: 7.64 g
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