A voltaic cell consists of an Al/Al3+ half-cell and an Fe2+/Fe3+ half-cell. Calculate Ecell when conc. of Fe2+= 0.402 M, Fe3+= 0.073 M and Al3+= 0.239 M. Use the reduction potentials for Al3+ is -1.66 V and for Fe3+ is 0.77 V.
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A voltaic cell consists of an Al/Al3+ half-cell and an Fe2+/Fe3+ half-cell. Calculate Ecell when conc....
A voltaic cell consists of an Al/Al3+ half-cell and a Cd/Cd2+ half-cell. Calculate {Cd2+} when {Al3+} = 0.306 M and Ecell = 1.27 V. Use reduction potential values of Al3+ = -1.66 V and for Cd2+ = -0.40 V.
A voltaic cell is constructed from a standard Fe2+|Fe half cell (E°red = -0.440V) and a standard Cl2|Cl- half cell (E°red = 1.360V) Anode Reaction: Cathode Reaction: Spontaneous Cell Reaction: Cell Voltage: ___ V A voltaic cell is constructed from a standard Fe2+|Fe half cell (E°red = -0.440V) and a standard Al3+|Al half cell (E°red = -1.660V). Anode Reaction: Cathode Reaction: Spontaneous Cell Reaction: Cell Voltage: ___ V
A voltaic cell consists of an Mn/Mn2+ half-cell and a Pb/Pb2+ half-cell. Calculate [Pb2+] when [Mn2+] is 2.5 M and Ecell = 0.23 V.
A voltaic cell consists of an Mn/Mn2+ half-cell and a Pb/Pb2+ half-cell. Calculate [Pb2+] when [Mn2+] is 2.1 M and Ecell = 0.35 V. _____M
Calculate Ecell (the reduction potential for the balanced chemical equation under nonstandard conditions) for the electrochemical cell shown below: Pt | Fe2+ (4.25x10-3 M), Fe3+ (1.50x10-3 M) || MnO4 - (6.50x10-3 M), Mn2+ (2.00x10-2 M), H+ (0.100 M) | Pt. Use the following standard reduction potentials for each half reaction. The Eo for Fe3+/Fe2+ = 0.77 V and Eo for MnO4 - /Mn2+ = 1.51 V.
1. A voltaic cell is constructed from a Al/Al half-cell (E'red -1.66 V) and a Fe/Fe? half- cell (Ered-0.44V) Give the oxidation half reaction and E"ox, the reduction half reaction and E'red, and the overall reaction and E"cell: Oxidation: Reduction: red E cell Overall Reaction: 2. For the cell Fe(s) Fe2+ | Pb* | Pb), the standard cell potential is +0.31 V. A cell using these reagents was made, and the observed potential was +0.37 V at 25°C. A) What...
A voltaic cell consists of a standard hydrogen electrode in one half-cell and a Cu/Cu2+ half-cell. Calculate [Cu2+] when Ecell is 0.22 VA voltaic cell consists of a standard hydrogen electrode in one half-cell and a Cu/Cu2+ half-cell. Calculate [Cu2+] when Ecell is 0.22 V
consider the following standard reduction potentials. Reduction Half-Reaction Eo (volts) Al3+(aq) + 3e− → Al(s) − 1.66 Fe2+(aq) + 2e− → Fe(s) − 0.44 Sn2+(aq) + 2e− → Sn(s) − 0.14 The Al/Al3+ half-reaction can be paired with the other two to produce voltaic cells because ________ A) Al is a more powerful oxidizing agent B) Fe and Sn are readily oxidized Al is a more powerful reducing agent C) Al3+ is a more powerful oxidizing agent D) Al3+...
Half-cell Potentials: Half Reaction: E value +0.80 V Agt + e → Ag Fe3+ + € → Fe2+ +0.77 v +0.34 V -0.13 V Cu2+ +2e → Cu Pb2+ + 2e - → Ib Ni2+ + 2e → Ni Cd2+ +2e → Cd -0.25 V -0.40 V Fe2+ + 2e → Fe -0.44 V Zn2+ + 2e → Zn -0.76 V Al3+ +3e → AI - 1.66 V Consider an electrochemical cell constructed from the following half cells, linked by...
What is the standard cell potential for a voltaic cell with the following line notation? Al(s)[A1+ (aq)||Fe3+ (aq) Fe(s) Give your answer to 3 significant figures. Half Reaction Eredº (V) Al3+ + 3e- → AI -1.66 Fe3+ + 3e- → Fe +0.771 Numeric Answer