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You are hired to design a reliable byte-stream protocol that uses a sliding window (like TCP)....

You are hired to design a reliable byte-stream protocol that uses a sliding window (like TCP). This protocol will run over a 1-Gbps network. The RTT of the network is 200 ms.

How many bits would you include in the AdvertisedWindow field of your protocol header? (choose the closest number that can satisfy the above requirement).

Hints:
- First, determine how much data to keep the pipe full (i.e. delay * bandwidth)
- Second, if we assume the window is measured in bytes then calculate how many bits are required in the AdvertisedWindow field to represent those data in pipe.

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Answer #1

The maximum amount of data that will fit is given by the Bandwidth Delay Product

Bandwidth Delay Product = Bandwidth x RTT = 1 Gbps x 200 ms = 25,000,000 bytes / sec

No. of bits needed in the window is

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