Question

Historically, the percentage of residents of a certain country who support stricter gun control laws has been 52%. A recent poll of 916 people showed 522 in favor of stricter gun control laws. Assume the poll was given to a random sample of people. Test the claim that the proportion of those favoring stricter gun control has changed. Perform a hypothesis​ test, using a significance level of 0.05.

State the null and alternative hypotheses.

H 0​: The population proportion that supports stricter gun control is 0.52​, p= Answer ____.

Ha​" p Answer ______ (Type integers or decimals. Do not​ round.)

The significance level is a= 0.05 Choose the​ one-proportion z-test, and check the conditions. Note that the sample is random and the observations are independent. Next check the Large Sample Size condition. The expected numbers of successes and failures are

np 0p0equals=916 times•0.520. 52 equals = about Anwser ____ which is more than​ 10, and ​n(1minus−0.52​)equals=about Answer _____which is more than Answer ___.The population size is more than 10 times 916. ​(Round to the nearest whole number as​ needed.)

Compute the sample proportion p^ ^p = Answer ____ (Round to four decimal places as​ needed.)

Calculate the values needed to compute the standard error.

SE=	equals=	pk(1-po)over n = 0.52(Answer____) Computer the standard error SE =Answer ________

​(Simplify your answer. Do not​ round.)

Compute the standard error. SE= Answer ___ ​(Round to four decimal places as​ needed.)

Compute the z-test statistic z = Answer____ (2 decimals places)

Compute p-value (3 decimals) p-value = Answer ____(3 decimal places)

Question>>>Reject Ho or do not reject Ho and interpret the conclusion is or is not siginificantly different than the %

Answer 1