Question

Historically, the percentage of residents of a certain country who support stricter gun control laws has been 51 %. A recent poll of 1032 people showed 576 in favos stricter gun control laws. Assume the poll was given to a random sample of people. Test the claim that the proportion of those favoring stricter gun control has cha Perform a hypothesis test, using a significance level of 0.05 Compute the standard error. SE 0.0156 (Round to four decimal places as needed.) Identify the values needed to compute the z-test statistic p-Po Z SE 0.5581- 0.51 SE (Type the terms of your expression in the same order as they appear in the original expression. Round to four decimal places as needed.) Compute the z-test statistic. z3.08 (Round to two decimal places as needed) Compute the p-value p-value (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer part remaining Clear All Check Answer

Answer 1

Here we have to test that

Ho: p=0.51

1907 d:H

Po = 0.51

n = 1032

x = number of people who are in favor of stricter gun control laws = 576

P = - n = 576 1032 = 0.5581

Test statistic:

SE

SE = Po* (1 - po)

SE 0.51 *(1 – 0.51) 1032

SE = 0.0156

10.5581-0.51 0.0156

z = 3.08              (Round to 2 decimal)

P value:

Test is two tailed test.

P value = 2 * P(z > 3.08)

            = 2 * (1-P(z < 3.08))

            = 2 * (1-0.9990)

             = 2 * 0.002

             = 0.004

P value = 0.004