The reaction is
H2SO4 + 2 NaOH ----------------> Na2SO4 + 2H2o
The relation of molarities at equivalence is
V1M1/n1 = V2M2/n2 where N1 and N2 are the stoichiometric coefficients of H2So4 and NaOH respectively.
23.00mL x M /1 = 25.67mL x 1.760M/2
Thus Molarity of H2SO4 ,M1 = 0.982 M
Alternatively
meq of acid = meq of base
2x23.00mL x Molarity = 1 x 25.67 mL x 1.760 M
[as H2SO4 is dibasic and NaOH is monoacidic]
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