Consider two fair, FOUR sided dice, with faces labeled 1, 2, 3, 4. Compute the probability of rolling
a) a sum of 3
b) a sum of 6
c) a sum of 9
d) the most likely sum(s) along with its probability.
Total number of possible combinations = 42 = 16
a)
Sum of 3: {(1,2),(2,1)}
Required probability =
b)
Sum of 6: {(2,4),(4,2),(3,3)}
Required probability =
c)
Sum of 9: {}
Required probability =
d)
Sum of 2: {(1,1)}
Sum of 3: {(1,2),(2,1)}
Sum of 4: {(1,3),(3,1),(2,2)}
Sum of 5: {(1,4),(4,1),(2,3),(3,2)}
Sum of 6: {(2,4),(4,2),(3,3)}
Sum of 7: {(3,4),(4,3)}
Sum of 8: {(4,4)}
Since sum 5 has maximum instances, so it is the most likely sum.
P(sum is 5) =
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