Question

Language: Python

Topic: Try/Except

Function name : add_divide

Parameters : list of ints, int

Returns: float

Description: Given a list of integers and a number, you want to add the numbers in the list to a total value by iterating through the given list. However, when the index you are at is divisible by the integer passed in, you must instead divide the current total by the element at that index. You must be careful when dividing the total (you can’t divide numbers by 0 or else an error will be thrown). Whenever you encounter this, instead of dividing, you must add one to the total. You also must use a try/except block for this problem. Also, round final answer to two decimal places.

Test Cases :
>>> tester1 = [9, 2, 0, 1, 0, 3, 4, 6, 5] >>> value1 = add_divide(tester1, 2) >>> print(value1)
1.6

>>> tester2 = [0, 1, 0, 2, 0, 3, 0, 4, 0, 5, 0, 6] >>> value2 = add_divide(tester2, 4)
>>> print(value2)
24

Answer 1

def add_divide(lst, n):
    result = 0
    for i in range(len(lst)):
        try:
            if i % n == 0:
                result /= lst[i]
            else:
                result += lst[i]
        except:
            result += 1
    return result


tester1 = [9, 2, 0, 1, 0, 3, 4, 6, 5]
value1 = add_divide(tester1, 2)
print(value1)

tester2 = [0, 1, 0, 2, 0, 3, 0, 4, 0, 5, 0, 6]
value2 = add_divide(tester2, 4)
print(value2)