Problem 4. PYTHON: (Root Finding) Write a program root.py (a variant of the sqrt.py program we discussed in class) that accepts k (int), c (float), and epsilon (float) as command-line arguments, and writes to standard output the kth root of c, up to epsilon decimal places.
Example: $ python3 root . py 3 2 1e -15
1.2599210498948732
Hints:
Set t (our guess) to c
Use the condition |1 − c/tk| > to continue the loop
At each iteration, replace the estimate t by t − f(t)/f0 (t), where f(t) = t k − c and f 0 (t) = ktk−1
The method described in the question is called Newton Raphson method. Below is the python code for the question. Copy it to a file called "root.py" and run it through command line as "python3 root.py 3 2 1e-15".
import sys
# Read command line arguments
args = sys.argv
k = int(args[1])
c = float(args[2])
e = float(args[3])
# At any iteration, 't' will hold the current
iteration's guess and 'prev_t' will hold the previous iteration's
guess
t = c
while True:
prev_t = t
ft = t**k - c
f0t = k*(t**(k-1))
t = t - ft/f0t
# If absolute differnt of previous guess and current
guess is less than equal to epsilon, then we have found our
answer
if abs(prev_t - t) <= e:
break
print("The answer is: {}".format(t))
Problem 4. PYTHON: (Root Finding) Write a program root.py (a variant of the sqrt.py program we...
Problem 4. (Root Finding) Write a program root.py (a variant of the sqrt.py program we dicussed in class) that accepts k (int), c (float), and epsilon (float) as command-line arguments, and writes to standard output the kth root of c, up to epsilon decimal places.
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